An elevator (mass 4125 kg) is to be designed so that the maximum acceleration is 0.0400g.
What is the maximum force the motor should exert on the supporting cable?
What is the minimum force the motor should exert on the supporting cable?

Respuesta :

The way to do this is very easy so do 4125 x 2 = ? then the ? will be times by 2 again after the answer to both of those is your answer!!!