Respuesta :
Redox reaction.....
2K(s) + Br2(l) --> 2KBr(s)
Potassium is oxidized. Bromine is reduced. Potassium metal is the reducing agent and Br2 is the oxidizing agent.
2K(s) + Br2(l) --> 2KBr(s)
Potassium is oxidized. Bromine is reduced. Potassium metal is the reducing agent and Br2 is the oxidizing agent.
2K+Br2->2KBr
Bromine is the oxidizer (+2ē)
Potassium is the reducer (-1ē)
Bromine is the oxidizer (+2ē)
Potassium is the reducer (-1ē)