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a force of 6lbs acts on an object with a weight of 35 lbs on earth. determine the objects acceleration. final answer must be 5.52ft/s^2

Respuesta :

yashddsy26
weight of body = 35 lbs
F = ma
m = F/a = 35/32 ( acceleration = 32 ft/s^2)
m= 1.09

so again using same formula,
a = F/m
a= 6/1.09
a= 5.489

or say, acceleration = 5.5 ft/s^2 !!

Answer:

The acceleration of the object is 5.5 ft/s².

Explanation:

Given that,

Force = 6 lbs

Weight = 35 lbs

We need to calculate the mass

Using newton's second law

[tex]F = mg[/tex]

[tex]m =\dfrac{F}{g}[/tex]

Put the value into the formula

[tex]m= \dfrac{35}{32.2}[/tex]

[tex]m=1.09\ lb[/tex]

We need to calculate the acceleration

Using newton's second law

[tex]F = ma[/tex]

Put the value into the formula

[tex]a =\dfrac{6}{1.09}[/tex]

[tex]a=5.5\ ft/s^2[/tex]

Hence, The acceleration of the object is 5.5 ft/s².

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