Answer:
Sample answer: First, draw and label a net of the pyramid. The triangular faces have a base of 5 yards and a height of 12 yards. Find the area of each of the faces. The square base has an area of 25 yd2. Each of the triangular faces has an area of 30 yd2. Add the areas together to find the surface area: 25 + 30 + 30 + 30 + 30 = 145 yd2.
Step-by-step explanation
The surface area of the pyramid with a square base is 145 square yards whose base dimensions are 5 yards by 5 yards and height of 12 yards.
In geometry, it is defined as the shape having a square base with equal sides length and all the vertex of the squares joints at the top which is perpendicular to the center of the square.
We have a square base of the pyramid has dimensions of 5 yards.
The height of one of the triangular faces = 12 yards
First, we calculate the area of square = (side)²
= 5² ⇒ 25 square yards
Now calculate the area of one triangular face:
[tex]\rm = \frac{1}{2} (a\times h)[/tex]
[tex]\rm = \frac{1}{2} (5\times12)[/tex] (a = 5 yards and h = 12 yards)
= 30 square yards
The area of four triangular faces = 4×30= 120 square yards
Now the surface area of the square base of a pyramid:
= 25 + 120
= 145 square yards.
Thus, the surface area of the pyramid with a square base is 145 square yards.
Learn more about the pyramid here:
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