A dump truck brought 1⁄3 of a ton of rock on the first trip, 5⁄6 of a ton on the second trip, and 5⁄12 of a ton on the third trip. What was the total weight of the rock?

First convert the numbers to get the same denominator
1/3=4/12
5/6=10/12
5/12
Then add them all together
4/12+10/12+5/12= 19/12
Then reduce
1 7/12
Your answer is 1 ton and 7/12 of a ton

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dgsistemasp0pffb dgsistemasp0pffb · Answer 2 · 2019-08-29T23:31:55+02:00

Answer:

Weight = [tex]1 and \frac{7}{12}[/tex] Ton

Step-by-step explanation:

The total weight of the rock is calculated by adding the three fractions.

Weight = [tex]\frac{1}{3}+\frac{5}{6}+\frac{5}{12}[/tex]

As they are different denominators, we look for a common denominator that is the Least Common Multiple (LCM).

Then, for each term, the LCM is divided by the denominator of the original fraction and multiplied by the numerator.

Weight = [tex]\frac{1}{3}+\frac{5}{6}+\frac{5}{12}[/tex]

Weight = [tex]\frac{(12/3*1) + (12/6*5) + (12/12*5)}{12}[/tex]

Weight = [tex]\frac{4+10+5}{12}[/tex]

Weight = [tex]\frac{19}{12}=1.5833[/tex] Ton

Or

Weight = [tex]\frac{19}{12}[/tex]

Weight = [tex]\frac{12+7}{12}[/tex]

Weight = [tex]\frac{12}{12}+\frac{7}{12}[/tex]

Weight = [tex]1+\frac{7}{12}[/tex]

Weight = [tex]1 and \frac{7}{12}[/tex] Ton

Hope this helps!