28. A gas has a volume of 590mL at a temperature of -55.0C. What volume will the gas occupy at 30.0C? Show your work.

According to Charles law, volume is directly proportional to the temperature at constant pressure.
So, V1/T1 = V2/T2
Here, V1 = 590 mL
T1 = -55 + 273 = 218 K
T2 = 30 + 273 = 303 K

Substitute their values,
590/218 = V2/303
V2 = 303*590 / 218
V2 = 820.05 mL

In short, Your Answer would be 820.05 mL

Hope this helps!

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mahima6824soni mahima6824soni · Answer 2 · 2022-02-02T06:29:31+01:00

The volume of the gas occupies at 30.0C is 820.05 ml.

What is Charles' Law?

According to Charles' law:

Charles' law shows how gas expands when it is heated.

The volume of a gas is directly proportional to the number of moles of gas under constant temperature and pressure.

[tex]\dfrac{V1}{T1} =\dfrac{V2}{T2}[/tex]

Given, temperature 1 = -55.0C

Temperature 2 = 30.0C

Temperature changes into Kelvin:

T1 = -55 + 273 = 218 K

T2 = 30 + 273 = 303 K

Now, from the equation of Charles' law:

[tex]\dfrac{590}{218} =\dfrac{V2}{303}[/tex]

[tex]V2 = \dfrac{590\times303}{218} = 820.05\; ml[/tex]

Thus, the volume will be V2 = 820.05 ml.

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