What are the next three terms of the geometric sequence 32, -16, 8, …? a. 2, 1, 1/2 c. -8, 16, -32 b. 4, 2, 1 d. -4, 2, -1 please select the best answer from the choices provided a b c d

Respuesta :

The given sequence is a geometric sequence and the next three terms are

-4, 2, -1

i.e  32, -16, 8, -4, 2, -1.

So option d is our correct answer.

The given sequence is 32, -16, 8, ...

We need to find what type of sequence is 32, -16, 8,... and calculate the next three terms that satisfy the given sequence.

i.e we need to find the [tex]4^{th},5^{th}~and~6^{th}~ term~of~the~sequence.[/tex]

What is a geometric sequence?

It is a sequence in which each term is found by multiplying the preceding term by a constant value 'r' called the common ratio.

Example: 4,8,16,32 where r = 2.

The formula used to find the nth term in a geometric sequence is:

[tex]a_n = a_1 ~r^{n-1}[/tex]  Where a_1 is the first term of the sequence.

We have the given sequence as 32, -16, 8,......

Find the common ratio.

r = -16 / 32 = -1 / 2r = 8 /-16 = -1 / 2

Here we see that each term is found by multiplying the previous term with a common ratio r = -1/2.

So the given sequence is a geometric sequence.

Here a_1 = 32.

Applying the nth term geometric sequence to find the [tex]4^{th},5^{th}~and~6^{th}~ term~of~the~sequence.[/tex]

We get,

[tex]a_4=a_1(\frac{-1}{2})^{4-1}\\\\a_4=32(\frac{-1}{2})^3\\\\a_4 = \frac{-32}{8}\\\\a_4=-4\\\\a_5=a_1(\frac{-1}{2})^{5-1}\\\\a_5=32(\frac{-1}{2})^4\\\\a_5 = \frac{32}{16}\\\\a_5=2\\\\a_6=a_1(\frac{-1}{2})^{6-1}\\\\a_6=32(\frac{-1}{2})^5\\\\a_6 = \frac{-32}{32}\\\\a_6=-1\\[/tex]

We see that the sequence is 32, -16, 8, -4, 2, -1.

The given sequence is a geometric sequence and the next three terms are -4, 2 and -1

i.e 32, -16, 8, -4, 2, -1

Learn more about  geometric sequences here:https://brainly.com/question/11266123

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