The probability that Naoya succeeds at any given free-throw is 70\pp, percent. He was curious how many free-throws he can expect to succeed in a sample of 151515 free-throws. He simulated 202020 samples of 151515 free-throws where each free-throw had a 0.70.70, point, 7 probability of being successful. Naoya counted how many free-throws were successful in each simulated sample. Here are his results:

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08-08-2022
Mathematics

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The probability that Naoya succeeds at any given free-throw is 70\pp, percent. He was curious how many free-throws he can expect to succeed in a sample of 151515 free-throws. He simulated 202020 samples of 151515 free-throws where each free-throw had a 0.70.70, point, 7 probability of being successful. Naoya counted how many free-throws were successful in each simulated sample. Here are his results:

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tutorconsortium350 tutorconsortium350 · Answer 1 · 2022-08-12T23:09:44+02:00

According to the results, there is a chance that he will make 11 or less free throws, with a probability of P(11 or fewer sucessess) = 0.22.

What is successive Probability?

Independent and dependent events in succession. Multiply the odds of the individual events to discover the likelihood that numerous occurrences will take place one after the other. Independent or dependent successive events are both possible. Independent occurrences don't have an impact on one another.

According to the given information :

He simulated 30 samples, so we're told. He made 10 free throws, 11 free throws, 12 free throws, 13 free throws, 14 free throws, and 15 free throws a total of 10 times, according to the dot plot.

His free throw success rate of 11 or less was achieved 6 times, according to the dot plot.

Thus;

P(11 or fewer success) = 6/30.

P(11 or fewer success) = 1/ 5.

P(11 or fewer victories) = 0.

there is a chance that he will make 11 or less free throws, with a probability of P(11 or fewer successes') = 0.22.

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