The general term of the given sequence is given by: [tex]5(\frac{1}{3}) ^{n-1}[/tex]
Geometric progression refers to a special progression, or a sequence of numbers, in which each successive term is a fixed multiple of the term preceding it.
For a geometric progression having first term 'a', a constant ratio of the terms be 'r' and 'n' number of terms, then:
General Term of Geometric Progression(G.P.) = [tex]ar^{n-1}[/tex], where r > 0.
Given: [tex]5,\frac{5}{3},\frac{5}{9},...[/tex]
Here, for the given G.P., a = 5, r = [tex]\frac{1}{3}[/tex]
Then, the general term = [tex]5(\frac{1}{3}) ^{n-1}[/tex], if the given G.P. has 'n' terms.
To learn more about geometric progressions, refer to the link: https://brainly.com/question/1509142
#SPJ4
