Ksp of Ag3PO4 will be 4.3 x 10 ^( -20) .
When a chemical substance in the solid form is in chemical equilibrium with a solution of that molecule, a solubility equilibrium is a sort of dynamic equilibrium that develops. The solid may dissolve chemically reacting with another component of the solution, such as acid or alkali, or dissolving unaltered.
Solubility of Ag3PO4 = 4.3 x 10 ^ (-5)
Ksp = [cation]ⁿ x [anion]ᵇ
where,
n : no . of moles of cation
b : no. of moles of anion
Ksp = (4.3 x 10 ^(-5)) ^ (4) = 4.3 x 10 ^( -20)
Therefore, Ksp = 4.3 x 10 ^( -20)
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