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A square that is 6 in on a side is placed inside a rectangle that has a length of 28 in and a width of 10 in. What is the area of the region inside the rectangle that surrounds the square?
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rainbowwarrior8000

Answer:This requires a couple of steps to solve: find the area of the square, find the area of the rectangle, and lastly finding the difference.

For the area of the square it is just the squaring the side length: A= s2

Asquare= (9 ft)2= 81 ft2

The area of the rectangle is the width times length: A=lw

Arectangle= 10 ft * 19 ft= 190 ft2

Now, to find the area of the region inside the rectangle that surrounds the square: Aregion= Arectangle-Asquare

A= 190 ft2-81 ft2= 109 ft2

if it doesn't answer youre question im sorry

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