In a Young's double-slit experiment, a thin sheet of mica is placed over one of the two slits. As a result, the center of the fringe pattern (on the screen) shifts so that the center is now occupied by what was the 30th dark band. The wavelength of the light in this experiment is 480 nm and the index of the mica is 1.60. The mica thickness is:

Respuesta :

The mica thickness will be  24 * [tex]10^{-6}[/tex] m

Diffraction of light is the phenomena of bending of light around the corner of an obstacle or aperture in the path of light and this light penetrates into the geometrical shadow of the obstacle. Thus, this light deviates from its linear path.

The central maximum is the brightest central portion of the diffraction pattern. The central maximum is the widest and has the maximum intensity.

Fringe width = lambda * D / d

The distance of the screen from the slit = D

The distance between two slits = d

shift = 30 * lambda  * D / d                               equation 1

shift in central maxima = (mu - 1)t D / d            equation 2

equating both the equations

(mu - 1) t D / d  = 30 * lambda  * D / d          

(1.60 - 1) * t    = 30 * 480 * [tex]10^{-9}[/tex]

t = 24 * [tex]10^{-6}[/tex] m

To learn more about diffraction here

https://brainly.com/question/13274373

#SPJ4