The sequence negative one fourth comma two fifths comma negative three sixths comma four sevenths and so on is given. Part A: Assuming the pattern continues, list the next four terms in the sequence. Show all necessary math work. (4 points) Part B: Write the explicit equation for f (n) to represent the sequence. Show all necessary math work. (4 points) Part C: Is the sign of f (59) positive or negative

Respuesta :

  • The next four terms in the sequence = [tex]\frac{-5}{8} , \frac{6}{9} ,\frac{-7}{10}[/tex][tex], \frac{8}{11}[/tex]
  • The explicit equation for f (n) to represent the sequence, [tex]f(n)=(-1)^{n} \frac{n}{n+3}[/tex]
  • The sign of f(59) is negative

Given,

The sequence: [tex]\frac{-1}{4} ,\frac{2}{5} ,\frac{-3}{6} ,\frac{4}{7} ...[/tex]

Part A: We have to find the next four terms in the sequence.

We can use the equation [tex]f(n)=(-1)^{n} \frac{n}{n+3}[/tex]

Where, n is the number of term.

For first term [tex]f(1)=(-1)^{1} \frac{1}{1+3} =(-1)\frac{1}{4} =\frac{-1}{4}[/tex]

Now, we can determine the next four terms in the sequence.

[tex]f(5)=(-1)^{5} \frac{5}{5+3} =(-1)\frac{5}{8} =\frac{-5}{8}[/tex]

[tex]f(6)=(-1)^{6} \frac{6}{6+3} =(1)\frac{6}{9} =\frac{6}{9}[/tex]

[tex]f(7)=(-1)^{7} \frac{7}{7+3} =(-1)\frac{7}{10} =\frac{-7}{10}[/tex]

[tex]f(8)=(-1)^{8} \frac{8}{8+3} =(1)\frac{8}{11} =\frac{8}{11}[/tex]

Part B: The explicit equation for f (n) to represent the sequence.

[tex]f(n)=(-1)^{n} \frac{n}{n+3}[/tex]

Where n is the number of term

Part C: The sign of f(59)

[tex]f(59)=(-1)^{59} \frac{59}{59+3} =(-1)\frac{59}{62} =\frac{-59}{62}[/tex]

From the above calculation it is clear that the sign of f(59) is negative.

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