The probability of flipping at least two heads in a row is 3/8.
Let E be an event of flipping atleast two heads in a row.
According to the given question.
A fair coin is flipped three times.
Therefore,
The sample space when a fair coin is flipped three times is
{HHH, HHT, HTH, HTT, THH, THT, TTH, TTT}
Where, H denotes of getting H and T denotes getting tail.
So, there is total eight possible outcomes we get when a fair coin is flipped.
Now, the total possible sequences or outcomes of getting or flipping atleast two heads in a row would be {HHH, HHT, THH}
⇒ Total number of favorable outcomes = 3
Therefore, the probability of flipping at least two heads in a row is given by
P(E) = number of favorable outcomes/total number of outcomes
⇒ P(E) = 3/8
Hence, the probability of flipping at least two heads in a row is 3/8.
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