A non-rigid balloon is held in a chamber set at 293 K and 1 atm of pressure. The balloon's volume is 0.05 m³. If the pressure in the room is increased to 5 atm, then the new volume of the balloon would be 0.01 meter³
It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one, the real gases approach the behaviors of an ideal gas at a very high temperature and very low pressure.
By using Boyle's law
P₁V₁=P₂V₂
Where P₁, and V₁, are initial pressure and volume
and P₂ and V₂, are the final pressure and volume
By substituting the values in the above equation
P₁ = 1 atm
V₁= 0.05 meter³
P₂ = 5.0 atm
V₂= ? meter³
The only unknown term which we have to find is the final volume of the balloon
1.0 ×0.05=5.0×V₂
V₂ =0.01 meter³
Thus, the new volume of the balloon would be 0.01 meter³
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