naarah84
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A 520kg rocket sled at rest is propelled along the ice by an engine developing a constant thrust of 12 000 N over a distance of 40 m. Assuming all of the work goes into motion, calculate a). The work done by the engine on the sled after 40 m b). Its velocity after 40 m (using the kinetic energy formula).​

Respuesta :

Answer:

a) 480 000 J

b) 43 m/s

Explanation:

a)

To calculate the work done by the engine, we can use the following formula:

[tex]\boxed{\mathrm{Work \space\ done = Force \times Distance}}[/tex].

                  ⇒ [tex]12000 \times 40[/tex]

                  ⇒ [tex]480000 \space\ \mathrm J[/tex]

b)

We know that the work done by the propeller was converted into motion of the sled, which means the propeller provided the sled with kinetic energy.

∴ work done by propeller = kinetic energy gained by sled

⇒ [tex]480000 = \frac{1}{2} mv^2[/tex]

⇒ [tex]480000 = \frac{1}{2} \times 520 \times v^2[/tex]

⇒ [tex]480000 = 260v^2[/tex]

⇒ [tex]v^2 = \frac{480000}{260}[/tex]

⇒ [tex]v =\bf 43 \space\ m/s[/tex]

This means that its velocity after 40 m was 43 m/s.