Find the electric energy density between the plates of a 225-μf parallel-plate capacitor. the potential difference between the plates is 390 v , and the plate separation is 0. 202 mm.

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The answer is 7.5824885 J/m^3.

Charge of the capacitor:

Q=C*potential difference = 225*10^-6*390=0.08775 C

Area of the plates:

A=(C*distance)/(epsilon)=(225*10^-6*0.298*10^-3 / 8.854 *10^-12 m^2 ) = 7.5728 * 10^3 m^2

E field of the capacitor is computed on the charge per area:

E=Q/(A*epsilon) = 1308733.20186 V/m

Electrical energy density = 0.5*epsilon*E^2= 7.5824885 J/m^3

What is Electrical energy density?

  • The amount of energy that may be stored in a system or area of space per unit of mass or volume is known as the electric energy density.
  • The formula for energy density "D" is given as D = E V. The system's overall energy is denoted by "E." The volume of the system you are using is represented by "V."

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