The concentration for the stock solution is 3.94 M
The chemical equation as
FeSCN² (aq) → Fe³⁺ (aq) + SCN⁻ (aq)
Kd = (Fe³⁺ ) (SCN⁻) / (FeSCN²)
Kd = 9.1 × 10⁻⁴
= x² / 4.0 - x
4.0 M is rather big of a concentration, so the approximation is fine to make since percent dissociation decreases as concentration increases.
9.1 × 10⁻⁴ = x² / 4.0
x = √4.0 × 9.1 × 10⁻⁴
= 0.063 M
Hence the concentration for stock solution is 0.063 M
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