Respuesta :

The Ph when 15ml of 0.26m HCl is titrated with 45ml of 0.10 NaOH is 12

The chemical equation is

HCl + NaOH --> H2O + NaCl

Moles of HCl

15mL × 0.26 mol  = 0.0039 moles HCl

Moles of NaOH

45mL × 0.10mol  = 0.0045 moles NaOH

If 1ml of HCl reats with 1ml of NaOH

0.0006 moles of NaOH will remain.

New molarity (moles/liter) in total of both liquids:

15mL + 45mL = 60mL = 0.060L

0.0006 / 0.060L moles = 0.01M NaOH

                                  = 1 x 10-2M NaOH

The concentration of OH- ion is easy to recognize in this reaction

pH + pOH = 14

pOH = - log ( [OH-])

pOH = - log(1x10-2) = 2

pH + 2 = 14

pH = 12

Hence the ph is 12

Learn more about the ph on

https://brainly.com/question/22390063

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