Respuesta :
If the linear distance on the screen from the central fringe to the first bright fringe above it is 5.28 cm, 9.19m is the separation of the slits.
The double-slit experiment is a proof in modern physics that light and matter can exhibit properties of both classically defined waves and particles. It also shows that quantum mechanical phenomena are fundamentally probabilistic.
The formula to be used here is:
Linear distance (y) = nλL / d
where n = bright fringe
L = distance of screen from slits
λ = wavelength
d = distance between slits
Plugging in the values we get,
0.0528 = 5.58×[tex]10^{-7}[/tex] × 8.70 / d
0.0528 = 48.546×[tex]10^{-7}[/tex] / d
d = 919.431818×[tex]10^{-7}[/tex]
d = 9.19m
The complete question is; Light with a wavelength of 558 nm passes through two slits and forms an interference pattern on a screen 8.70 m away. If the linear distance on the screen from the central fringe to the first bright fringe above it is 5.28 cm, what is the separation of the slits
Learn more about bright fringe here;
https://brainly.com/question/12732324
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