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Answer:

  25 yards long, 5 yards wide

Step-by-step explanation:

The given parameters can be used with the area and perimeter formulas for a rectangle to form an equation that can be solved for the dimensions.

Setup

The length and width can be represented by x and y. The formulas for area and perimeter give two equations relating these two variables:

  A = LW   ⇒   125 = xy

  P = 2(L+W)   ⇒ 60 = 2(x +y)

Using the second equation to write an expression for y, we have ...

  y = 30 -x

Substituting into the first equation gives ...

  125 = x(30 -x)

Solution

This suggests we can find x by looking for factors of 125 that total 30.

  125 = 1(125) = 5(25)

Factor totals are 126 and 30. This means we have ...

  x = 5, y = 30-5 = 25

or

  x = 25, y = 30 -25 = 5

The rectangle dimensions are 5 yards by 25 yards.

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Additional comment

The two equations can also be solved graphically, as in the attachment.

Ver imagen sqdancefan

The rectangle will be 25 yards long, and 5 yards wide.

What is an area?

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called the area of the rectangle.

The given parameters can be used with the area and perimeter formulas for a rectangle to form an equation that can be solved for the dimensions.

The length and width can be represented by x and y. The formulas for area and perimeter give two equations relating to these two variables:

 A = LW   ⇒   125 = xy

 P = 2(L+W)   ⇒ 60 = 2(x +y)

Using the second equation to write an expression for y, we have ...

y = 30 -x

Substituting into the first equation gives ...

125 = x(30 -x)

This suggests we can find x by looking for factors of 125 that total 30.

125 = 1(125) = 5(25)

Factor totals are 126 and 30. This means we have.

x = 5, y = 30-5 = 25

x = 25, y = 30 -25 = 5

Therefore, the rectangle will be 25 yards long, and 5 yards wide.

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