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Answer:
25 yards long, 5 yards wide
Step-by-step explanation:
The given parameters can be used with the area and perimeter formulas for a rectangle to form an equation that can be solved for the dimensions.
Setup
The length and width can be represented by x and y. The formulas for area and perimeter give two equations relating these two variables:
A = LW ⇒ 125 = xy
P = 2(L+W) ⇒ 60 = 2(x +y)
Using the second equation to write an expression for y, we have ...
y = 30 -x
Substituting into the first equation gives ...
125 = x(30 -x)
Solution
This suggests we can find x by looking for factors of 125 that total 30.
125 = 1(125) = 5(25)
Factor totals are 126 and 30. This means we have ...
x = 5, y = 30-5 = 25
or
x = 25, y = 30 -25 = 5
The rectangle dimensions are 5 yards by 25 yards.
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Additional comment
The two equations can also be solved graphically, as in the attachment.

The rectangle will be 25 yards long, and 5 yards wide.
What is an area?
The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called the area of the rectangle.
The given parameters can be used with the area and perimeter formulas for a rectangle to form an equation that can be solved for the dimensions.
The length and width can be represented by x and y. The formulas for area and perimeter give two equations relating to these two variables:
A = LW ⇒ 125 = xy
P = 2(L+W) ⇒ 60 = 2(x +y)
Using the second equation to write an expression for y, we have ...
y = 30 -x
Substituting into the first equation gives ...
125 = x(30 -x)
This suggests we can find x by looking for factors of 125 that total 30.
125 = 1(125) = 5(25)
Factor totals are 126 and 30. This means we have.
x = 5, y = 30-5 = 25
x = 25, y = 30 -25 = 5
Therefore, the rectangle will be 25 yards long, and 5 yards wide.
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