The Volume of Water produced is 1.8 cm^3
Calculation:
O2 at STP has a molar volume of 22400 cm^3/mol.
Number of free moles of O2 = (1120 cm^3) / (22400 cm^3/mol) = 0.05 mol
According to the equation, mole ratio H₂O : O₂ = 2 : 1
No. of moles of H₂O produced = (0.05 mol) × 2 = 0.1 mol
H2O's molar mass = (1×2 + 16) g/mol, = 18 g/mol.
generated mass of H2O = (0.1 mol) ×(18 g/mol) = 1.8 g
Volume of water created = (1.8 g) (1 cm^3/g) = 1.8 cm3
To learn more about volume visit:
https://brainly.com/question/1578538
#SPJ4
