Respuesta :
A mixture of gases contains 1.50 mol of o2, 0.75 mol of he, and 2.25 mol of n2. the total pressure exerted by the mixture is equal to 2.50 atm .The partial pressure of the he will be 4.167 atm .
Each constituent gas in a mixture of gases has a partial pressure which is the notional pressure of that constituent gas if it alone occupied the whole volume of the original mixture at the same temperature.
given
moles of O2 = 1.50 moles
moles of He = 0.75 moles
moles of N2 = 2.25 moles
total moles = 1.50 + 0.75 + 2.25 = 4.50 moles
total pressure exerted by the mixture is = 2.50 atm
partial pressure of He = (moles of He / Total moles) * total pressure
= (0.75 / 4.50) * 25 = 4.167 atm
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