If the frequency of the block is 0.72 Hz , what is the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy

Respuesta :

0.136 s is the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy.

What is Hormonic Oscillator?

A harmonic oscillator is a system that, when displaced from its equilibrium position, experiences a restoring force F proportional to the displacement x, where k is a positive constant.

What is angular frequency?

  • An object's rotation or oscillation with regard to time is measured by its angular frequency, a scalar physical quantity.
  • Usually, it is indicated by the Greek letter ω.
  • The SI unit is radians per second, or rpm, is used to measure it (revolutions per minute). It deviates by a factor of two from frequency.

Calculation of angular frequency:

frequency of system = f

time = t

angular frequency = ω

amplitude = A

spring constant = k

mass = m

The angular frequency = 2[tex]\pi[/tex]. f

= 2[tex]\pi[/tex]f

= [tex]2\pi (0.72s^{-1} )[/tex]

= 4.5216[tex]s^{-1}[/tex]

The phase constant φ is zero since the system is no longer at rest.

The elastic potential energy U of the spring must be divided by the kinetic energy K of the block.

[tex]K = \frac{1}{2} U[/tex]

[tex]tan^{2}[/tex](ωt) = 0.5

Calculation of time t:

ωt = [tex]tan^{-1} (\sqrt{0.5} )[/tex]

t = 0.6155/ω

= 0.6155/4.5216 rad/s

= 0.136 s

Hence, 0.136 s is the earliest time after the block is released that its kinetic energy is exactly one-half of its potential energy.

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