Which postulate or theorem can be used to prove that ABC=DCB?
A.) SSS
B.) SAS
C.) ASA
D.) AAS

Answer:
A
Step-by-step explanation:
Givens
AB = DC Given
AC = BD Given
Solution and answer
AB = DC Given
AC = BD Given
BC = BC Reflexive property
ΔABC = ΔCDB SSS
Answer
SSS No angles are needed.
[tex]\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}[/tex]
Given:
▪ [tex]\longrightarrow \sf{ABC=DCB}[/tex]
[tex]\leadsto[/tex] Two triangles are congruent if three sides of one are equal to three sides of the other. Therefore, for the given figure, as we can see, the three sides of the triangles are congruent, so we can state that ABC-DCB because of SSS.
[tex]\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}[/tex]