Respuesta :
The answer is [tex]\frac{d}{D}=n_{a} \mid n_{w}[/tex]
Given that,
If the distance to the object is more than about [tex]$0.4^{m}$[/tex], Then you can use the Small-angle approximation [tex]$(\tan \theta)=\theta$[/tex].
Need to find the formula for the distance D to the object, if you make use of the approximation.
Now,
We are expressing the answer in the terms of [tex]$\theta_{w}$[/tex] and l.
[tex]$D=l \mid \theta_{w}$[/tex]
Now, use the expression found in part c for the distance between your eyes and the object at point O, and find the ratio of the apparent distance to the real distance d/D.
Remember that the apparent distance is the distance calculated by your eyes using the angle [tex]$\theta_{a}$[/tex],instead of the angle [tex]$\theta_{w}$[/tex].
Since we are dealing with small angles, you nay We the approximations [tex]$\sin (x) \approx x$[/tex] and [tex]$a \sin (x) \approx x$[/tex]Exress your answer in terms of[tex]$n_{w}$[/tex] and $n_{a}$.
[tex]\frac{d}{D}=n_{a} \mid n_{w}[/tex]
What is distance ?
- Distance is the sum of an object's movements, regardless of direction.
- Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.
- While distance and displacement appear to have the same meaning, they actually have very different definitions and implications.
- Displacement is the measurement of "how far an object is out of place," whereas distance refers to "how much ground an object has covered during its motion." Let's examine the distinction between distance and displacement in this post.
To learn more about to distance visit?
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