Answer:
I'll assume f(a). =-2ax2-5a+4 is supposed to read f(a) = -2a^2-5a+4. There is no definition of "x" in this problem.
If so, f(-3) = 1
Step-by-step explanation:
f(a) =-2ax^2-5a+4
f(-3) =-2(-3)^2-5(-3)+4
f(-3) =-2(9) + 15+4
f(-3) =-18 + 19
f(-3) = 1
The value of function f(x). =-2ax² -5a + 4 at a = -3 will be -23a + 2.
The machine will only accept specified inputs, described as the function's domain, and will potentially produce one output for each input.
For example y = sinx , y = x + 3 ets.
Given,
f(x) = - 2ax² -5a + 4
x = -3
f(-3) = - 2a(-3)² -5a + 4
f(-3) = -18a - 5a + 4
f(-3) = 23a + 2
Hence the value of function f(x). =-2ax² -5a + 4 at a = -3 will be -23a + 2.
For more about the function
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