Odell and Kershaw run for minutes on a circular track. Odell runs clockwise at and uses the inner lane with a radius of meters. Kershaw runs counterclockwise at and uses the outer lane with a radius of meters, starting on the same radial line as Odell. How many times after the start do they pass each other

Respuesta :

The correct number times to travel radius is 47 .

What is Radius ?

  • Radius is defined as a line member joining the center to the boundary of a circle or a sphere. The length of the compass remains the same from the center to any point on the circumference of the circle or sphere. It's half of the length of the periphery.
  • In figure, the compass is defined as a line member joining the center of the circle or a sphere to its circumference or boundary. It's an important part of circles and spheres which is generally shortened as' r'.
  • The plural of compass is" diameters" which is used when we talk about further than one compass at a time. The largest line member in a circle or sphere joining any points lying on the contrary side of the center is the periphery, and the length of the compass is half of the length of the periphery. It can be expressed as d/ 2, where'd' is the periphery of the circle or sphere.

We first find the amount of minutes, k, until Odell and Kershaw's next meeting. Let a be the angle in radians between their starting point and the point where they first meet, measured counterclockwise. Since Kershaw has traveled 300k meters at this point and the circumference of his track is  ,  .

Similarly, . Since Odell has traveled 250k meters in the opposite direction and the circumference of his track is .

Solving for a in the second equation, we get . Then, from the first equation, we have .

Solving for k, we get k = . After k minutes, they are back at the same position, except rotated, so they will meet again in k minutes. So the total amount of meetings is .

Hence,

47 times after the start they pass each other.

Learn more about radius here:

https://brainly.com/question/24375372

#SPJ4

If Odell runs at a speed of 250 meters per minute and Kershaw runs at a speed of 300 meters per minute for 30 minutes when the radii are 50 meters and 60 meters then they will pass 23 times each other.

Given that Odell runs at a speed of 250 meters per minute and Kershaw runs at a speed of 300 meters per minute for 30 minutes and the radii are 50 meters and 60 meters

We are required to find the number of times Odell and Kershaw meets each other.

Circumference of the lane for Odell=2*3.14*50=314 meters.

Circumference of the lane for Kershaw=2*3.14*60=376.8 meters.

Distance that Odell covers in 30 minutes at a speed of 250 meters per minute=250*30=7500 meters.

Distance that Kershaw covers in 30 minutes at a speed of 300 meters per minute=300*30=9000 meters.

Rounds made by Odell=7500/314=23.88

Rounds made by Kershaw=9000/376.8=23.88

So they meets 23 times each other.

Hence if Odell runs at a speed of 250 meters per minute and Kershaw runs at a speed of 300 meters per minute for 30 minutes when the radii are 50 meters and 60 meters then they will pass 23 times each other.

Question is incomplete as the following information should be included:

Odell runs at a speed of 250 meters per minute and Kershaw runs at a speed of 300 meters per minute for 30 minutes and the radii are 50 meters and 60 meters.

Learn more about speed at https://brainly.com/question/4931057

#SPJ4