Respuesta :
notice, you've got a diameter in inches
and a linear velocity in miles
thus, you'd need to convert first
[tex]\bf v=rw\implies \cfrac{v}{r}=w\qquad \begin{cases} v=\textit{linear speed}\\ r=radius\\ w=\textit{angular speed}\\ --------------\\ v=20\frac{mi}{h}\\ r=\frac{diameter}{2}=\frac{27}{2} \end{cases} \\\\ \textit{now, converting 20miles to inches} \\\\ \cfrac{20mi}{h}\cdot \cfrac{5280ft}{mi}\cdot \cfrac{12in}{ft}\implies \cfrac{20\cdot 5280\cdot 12\ in}{h}\impliedby v \\\\\\ \cfrac{1267200\frac{in}{h}}{\frac{27}{2}in}=w[/tex]
now, whatever that is, you'll need to divide it by a revolution, recall, a revolution is [tex]2\pi[/tex]
thus [tex]\bf \cfrac{\qquad \boxed{\cfrac{1267200\frac{in}{h}}{\frac{27}{2}in}}\qquad }{2\pi }=revolutions[/tex]
and a linear velocity in miles
thus, you'd need to convert first
[tex]\bf v=rw\implies \cfrac{v}{r}=w\qquad \begin{cases} v=\textit{linear speed}\\ r=radius\\ w=\textit{angular speed}\\ --------------\\ v=20\frac{mi}{h}\\ r=\frac{diameter}{2}=\frac{27}{2} \end{cases} \\\\ \textit{now, converting 20miles to inches} \\\\ \cfrac{20mi}{h}\cdot \cfrac{5280ft}{mi}\cdot \cfrac{12in}{ft}\implies \cfrac{20\cdot 5280\cdot 12\ in}{h}\impliedby v \\\\\\ \cfrac{1267200\frac{in}{h}}{\frac{27}{2}in}=w[/tex]
now, whatever that is, you'll need to divide it by a revolution, recall, a revolution is [tex]2\pi[/tex]
thus [tex]\bf \cfrac{\qquad \boxed{\cfrac{1267200\frac{in}{h}}{\frac{27}{2}in}}\qquad }{2\pi }=revolutions[/tex]
Data:
Speed = 20 miles/hour [tex]\stackrel{converting}{\rightarrow} [/tex] 352 inches/sec
diameter of wheel (length) = 27 inches
Solving:
Dividing the initial speed of 352 inches per second by the length of 27 inches we have:
[tex] \frac{352\diagup\!\!\!\!\!in/sec}{27\diagup\!\!\!\!\!in} \approx 13.037\:revolutions\:per\:seconds[/tex]
Turning revolutions per second into revolutions per minute, we have:
revolutions per second_____revolutions per minute
1 [tex]\stackrel{converting}{\longrightarrow}[/tex] 60
13.037 [tex]\stackrel{converting}{\longrightarrow}[/tex] y
[tex] \frac{1}{13.037} = \frac{60}{y} [/tex]
multiply cross
[tex]1*y = 13.037*60[/tex]
[tex]y = 782.22\to\:\boxed{\boxed{y\approx782\:revolutions\:per\:minute}}\end{array}}\qquad\quad\checkmark[/tex]
Speed = 20 miles/hour [tex]\stackrel{converting}{\rightarrow} [/tex] 352 inches/sec
diameter of wheel (length) = 27 inches
Solving:
Dividing the initial speed of 352 inches per second by the length of 27 inches we have:
[tex] \frac{352\diagup\!\!\!\!\!in/sec}{27\diagup\!\!\!\!\!in} \approx 13.037\:revolutions\:per\:seconds[/tex]
Turning revolutions per second into revolutions per minute, we have:
revolutions per second_____revolutions per minute
1 [tex]\stackrel{converting}{\longrightarrow}[/tex] 60
13.037 [tex]\stackrel{converting}{\longrightarrow}[/tex] y
[tex] \frac{1}{13.037} = \frac{60}{y} [/tex]
multiply cross
[tex]1*y = 13.037*60[/tex]
[tex]y = 782.22\to\:\boxed{\boxed{y\approx782\:revolutions\:per\:minute}}\end{array}}\qquad\quad\checkmark[/tex]