The combustion of ethylene proceeds by the reaction When the rate of disappearance of O2 is 0.47 M s-1, the rate of disappearance of C2H4 is ________ M s-

Respuesta :

The rate of disappearance is 0.1566 M/s.

C2H4 (g)+3O2 (g)→2CO2 (g)+2H2O (g)

The reaction's rate is R R= -1/1 d[C2H4]/dt = -1/3 d[O2]/dt.

R=\frac{1}{2}\frac{d[CO 2]}{dt}=\frac{1}{2}\frac{d[H 2O]}

O2 disappearance rate is 0.47 M/s.

Rate of O2 dissolution is 3x R 0.47 M/s, or 3x R R =0.1566 M/s.

Rate of disappearance of C2H4 is equal to 1 x R d[C2H4]/dt, or 0.1566 M/s.

C2H4 dissipates at a rate of 0.1566 M/s.

There is a 0.1566 M/s rate of disappearance.

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