Respuesta :
1.6 x 10^19 electrons per coulomb
current (amperes) is defined as the number of coulombs per sec flow
amps = #of electrons /( electrons per coulomb) / 60 sec
= 3.4 x 10^19 electrons /1.6 x 10^19 electrons per coulomb /60 sec
= .035 amps
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current (amperes) is defined as the number of coulombs per sec flow
amps = #of electrons /( electrons per coulomb) / 60 sec
= 3.4 x 10^19 electrons /1.6 x 10^19 electrons per coulomb /60 sec
= .035 amps
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Answer : I = 0.0906 A.
Explanation :
It is given that,
No of electrons flowing in a wire, [tex]q=3.4\times 10^{19}[/tex]
We know that the charge on an electron is given by, [tex]q_e=1.6\times 10^{-19}\ C[/tex]
So the total charge becomes:
[tex]q=3.4\times 10^{19}\times 1.6\times 10^{-19}\ C[/tex]
[tex]q=5.44\ C[/tex]
We know that the current in wire is defined as, [tex]I=\dfrac{q}{t}[/tex]
[tex]I=\dfrac{5.44\ C}{60\ s}[/tex]
[tex]I=0.0906\ A[/tex]
Hence, this is the required solution.
