The charge q₁ on the particle is about 7.25 × 10⁻¹⁶ C
Electric charge consists of two types i.e. positively electric charge and negatively electric charge.
There was a famous scientist who investigated about this charges. His name is Coulomb and succeeded in formulating the force of attraction or repulsion between two charges i.e. :
[tex]\large {\boxed {F = k \frac{Q_1Q_2}{R^2} } }[/tex]
F = electric force (N)
k = electric constant (N m² / C²)
q = electric charge (C)
r = distance between charges (m)
The value of k in a vacuum = 9 x 10⁹ (N m² / C²)
Let's tackle the problem now !
Given:
diameter of charged particle = d = 1 μm
electric field strength = E = 1.00 × 10⁵ N/C
drag force = F = 7.25 × 10⁻¹¹ N
Unknown:
charge of particle = q₁ = ?
Solution:
The drag forces is caused by the electric force acting on the charge particles.
[tex]F = q_1 \times E[/tex]
[tex]7.25 \times 10^{-11} = q_1 \times 1.00 \times 10^5[/tex]
[tex]q_1 = (7.25 \times 10^{-11}) \div (1.00 \times 10^5)[/tex]
[tex]q_1 = 7.25 \times 10^{-16} ~ \text{Coulomb}[/tex]
Grade: High School
Subject: Physics
Chapter: Static Electricity
Keywords: Series , Parallel , Measurement , Absolute , Error , Combination , Resistor , Resistance , Ohm , Charge , Small , Forces
