Respuesta :
4.1 h = 14760 s
t 1/2 = ln 2 / k
k = rate reaction = 4.97 x 10^-5
ln 0.045 / 0.36 = - 4.97 x 10^-5 t
2.08 = 4.97 x 10^-5 t
t = 41839.9 s = 11 h 37 min 19 s
t 1/2 = ln 2 / k
k = rate reaction = 4.97 x 10^-5
ln 0.045 / 0.36 = - 4.97 x 10^-5 t
2.08 = 4.97 x 10^-5 t
t = 41839.9 s = 11 h 37 min 19 s
The formation of the product by the splitting of the reactant is called a decomposition reaction. It will take 11 h 37 min 19 s for the concentration to drop.
What is a first-order reaction?
In the first-order reactions, the rate of the reaction is in linear relation to the concentration of a single reactant.
Given,
Half life of the reaction = 14760 sec
Reaction rate (k) = [tex]4.97 \times 10^{-5}[/tex]
Initial concentration = 0.36 M
Final concentration = 0.045 M
Time (t) is calculated as:
[tex]\begin{aligned} \rm t \dfrac {1}{2} &= \dfrac{0.693}{\rm k}\\\\2.08 &= 4.97 \times 10^{-5} \;\rm \times t\\\\&= 41839.9 \;\rm s\end{aligned}[/tex]
Therefore, it will take 11 h 37 min 19s for the concentration to drop from 0.36 M to 0.045 M.
Learn more about the first-order reaction here:
https://brainly.com/question/15494549