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Balance the equation below, and answer the following question: What volume of chlorine gas, measured at STP; is needed to complete the reaction with 6.25g of sodium metal

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MissPhiladelphia
The balanced chemical reaction would be expressed as follows:

2Na + Cl2 = 2NaCl

We are given the amount of sodium metal to be used reaction. This would be the starting value for the calculations. We do as follows:

6.25 g ( 1 mol / 22.99 g ) ( 1 mol Cl2 / 2 mol Na ) ( 22.4 L / 1 mol ) = 3.045 L Cl2 needed

Hope this answers the question.

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