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Determine the molecular formula of a compound with an empirical formula of NH2 and a formula mass of 32.06 amu

Respuesta :

Answer:N2H4

Explanation: Empirical Formula, EF= NH2

Mass of the EF = mass of Nitrogen + mass of Hydrogen

EF = 14.007 + 1.008

= 15.015

Then, divide the given formula mass by the EF. That is,

32.06/15.015 = 2.135 = 2 (to the nearest whole number) ......... (1)

To get the molecular formula, multiple the empirical formula with the number from the equ (1) above.

Molecular formula = 2[NH2] = N2H4

The empirical formula is defined as the simplest whole-number ratio of atoms present in a compound. A molecular formula determines the number of atoms present in each element of the compound.

The molecular formula of a given compound is [tex]\rm N_2H_4[/tex].

Given:

  • Empirical formula = [tex]\rm NH_2[/tex]
  • Mass of [tex]\rm NH_2[/tex] = mass of Nitrogen + mass of hydrogen = 15.01
  • Formula mass of [tex]\rm NH_2[/tex] = 32.0 amu

To find the molecular formula, we get:

Molecular formula = [tex]\dfrac{32.06}{2.135}[/tex] = 2 (nearest whole number)

Multiplying the empirical formula with the value of the molecular formula obtained above, we get:

Molecular formula:

[tex]2 \times \rm NH_2[/tex] = [tex]\rm N_2H_4[/tex]

Thus, the molecular formula of a given compound is [tex]\rm N_2H_4[/tex].

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