contestada

Taking the density of air to be 1.29 kg/m^3, what is the magnitude of the linear momentum of a cubic meter of air moving with the following wind speed of 15 km/h?

Respuesta :

osprey2015
Density = mass divided by volume.So, the mass = density times volume.mass = 1.29 x 1 kglinear momentum is defined as mass times velocityso the linear momentum of a cubic metre at 15,000 m per hour would be 1.29 x 15km/h. The units would be kg km/h, which are not the SI units. These are kg m/s. To get to them the speed has to be converted into metres per second.
Chlidonias

Answer:

Momentum p = 5.375 kgm/s

Explanation:

Given

Density [tex]\rho = 1.29 kg/m^3[/tex]

Volume [tex]V = 1 m^3[/tex]

Velocity [tex]v = 15 km/h[/tex]

Solution

Mass  = Density x  volume

[tex]m = \rho \times V\\\\m = 1.29 \times 1\\\\ m = 1.29 kg[/tex]

velocity

[tex]v = 15 km/h\\\\v = \frac{15}{3.6} m/s\\\\v = 4.17 m/s[/tex]

Momentum = mass x velocity

[tex]p = m \times v\\\\p = 1.29 \times 4.17\\\\p=5.375 kgm/s[/tex]

Otras preguntas