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A 40 kg-skier starts at the top of a 12-meter high slope. At the bottom, she is traveling 10 m/s. How much energy does she lose to friction? A.She doesn't lose any because mechanical energy is always conserved.
B.4,704 J
C. 2,000 J
D.2,704 J

Respuesta :

HomertheGenius
E p = m g h = 40 kg * 9.8 m/s² * 12 m = 4,704 J
E k = m v² / 2 = 40 kg * ( 10 m/s ) ² / 2 = 2,000 J
4,704 J - 2,000 J = 2,704 J
Answer:
D ) 2,704 J

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