Answer with explanation:
Sum of interior angles of any polygon having , n sides = (n-2)×180°
It is given that, sum of interior of any polygon =300°
A.T.Q
→ (n-2)×180=300
[tex]n-2=\frac{300}{180}\\\\ n=2+\frac{30}{18}\\\\n=\frac{66}{18}\\\\ n=3\frac{2}{3}[/tex]
→Means that ,number of sides of the polygon is a fraction,which is Impossible.
Hence, we can conclude that,it is Impossible to have, 300 degrees in the sum of the interior angles of a polygon.
Option C: Never
Answer:
Answer with explanation:
Sum of interior angles of any polygon having , n sides = (n-2)×180°
It is given that, sum of interior of any polygon =300°
A.T.Q
→ (n-2)×180=300
→Means that ,number of sides of the polygon is a fraction,which is Impossible.
Hence, we can conclude that,it is Impossible to have, 300 degrees in the sum of the interior angles of a polygon.
Option C: Never
Step-by-step explanation:
