Respuesta :
Answer:
Given the equation: [tex]4(3-x)^{\frac{4}{3}} -5 = 59[/tex]
Add 5 to both sides we have;
[tex]4(3-x)^{\frac{4}{3}} = 64[/tex]
Divide by 4 both sides we have;
[tex](3-x)^{\frac{4}{3}} =16[/tex]
or
[tex]3-x = (16)^{\frac{3}{4}[/tex]
Using exponent rules;
[tex]a^{\frac{n}{m}} = (\sqrt[m]{a})^n[/tex]
then;
[tex]3-x =( \sqrt[4]{16})^3[/tex]
Simplify:
[tex]3-x = (2)^3[/tex]
or
[tex]3-x = 8[/tex]
subtract 3 from both sides we have;
[tex]-x = 5[/tex]
Divide both sides by -1 we get
[tex]x = -5[/tex]
Therefore, the solution for the given equation is, -5
