Data:
[tex] \frac{2}{3}\:cup\:of\:soup\longrightarrow\:1\:(each\:bowl)[/tex]
[tex]40\:cups\:of\:soup\longrightarrow\:?\:(each\:bowl)[/tex]
Solving: (They are proportional measures, the rule of three is made (directly proportional)
[tex] \frac{ \frac{2}{3}}{40} = \frac{1}{y} [/tex]
multiply cross
[tex] \frac{2}{3}*y = 40*1[/tex]
[tex] \frac{2y}{3} = 40[/tex]
multiply cross
[tex]2y = 3*40[/tex]
[tex]2y = 120[/tex]
[tex]y = \frac{120}{2}[/tex]
[tex]\boxed{\boxed{y =60\:bowls}}\end{array}}\qquad\quad\checkmark[/tex]
