ashheart12
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The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units.
What is BC, the height of the pyramid?
7 units
7 sqrt2 units
14 units
14 sqrt2 units

The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 14 units What is BC the height of the pyramid 7 units 7 sqrt2 units 14 class=

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MissPhiladelphia
In order to solve this problem, we need our knowledge on trigonometric functions and use it here to determine the height. We see that a right triangle is being formed where the height is involved. We calculate as follows:

tan 45 = opposite side / adjacent side
tan45 = height / 14
height = 14 square units

Third option is the correct answer.
ogorwyne

The height of the pyramid BC is equal to 14 units.

We have a right angled triangle BAC

Using the trigonometric formula

[tex]tangent = \frac{opposite}{adjacent} [/tex]

The tangent here = 45°

The opposite side, h (this is the side that is facing the angle)

The adjacent = 14°

This is due to the fact AD=DC=AC

When we put the values into the formula:

[tex]Tan45=\frac{h}{14} [/tex]

Tan 45= 1

  • When we cross multiply,

14*1 = h

Therefore the height of the pyramid BC is 14 units.

Read more on height of the pyramid here

https://brainly.com/question/12903285

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