Respuesta :
a. The model that I developed for the given data was established through the use of a scientific calculator and the answer is,
y = 2.43x - 8.85
b. Substitute 5 go the x of the model above,
y = (2.43)(5) - 8.85 = 3.3
c. Substitute 25.1 in the y of the model,
25.1 = (2.43)(x) - 8.85 ; x = 13.97 minutes
d. No, the slopes may be changing. We are only normalizing it by forming the model.
y = 2.43x - 8.85
b. Substitute 5 go the x of the model above,
y = (2.43)(5) - 8.85 = 3.3
c. Substitute 25.1 in the y of the model,
25.1 = (2.43)(x) - 8.85 ; x = 13.97 minutes
d. No, the slopes may be changing. We are only normalizing it by forming the model.
I used microsoft excel 2016 to graph the given data.
a) What is the equation for the model of best fit?
The equation is y = 2.43x - 8.85
b) What does your model predict would have been the amount present at 5 minutes?
The model predict when at 5 minutes, the amount is 3.3g.
y = 2.43x - 8.85
y = 2.43(5) - 8.85
y = 3.3g
c) At what time would 25.1 grams be produced, according to your model?
The model predict when at 25.1g, the time is 13.97min.
y = 2.43x - 8.85
25.1 = 2.43x - 8.85
x = 13.97min
a) What is the equation for the model of best fit?
The equation is y = 2.43x - 8.85
b) What does your model predict would have been the amount present at 5 minutes?
The model predict when at 5 minutes, the amount is 3.3g.
y = 2.43x - 8.85
y = 2.43(5) - 8.85
y = 3.3g
c) At what time would 25.1 grams be produced, according to your model?
The model predict when at 25.1g, the time is 13.97min.
y = 2.43x - 8.85
25.1 = 2.43x - 8.85
x = 13.97min