Answer:
Length of the fence will be = 282.84 feet
Step-by-step explanation:
The Blackburn family has a square field to keep their cattle. Area of the field is $40000 square feet.
Then one side of the square field will be = √Area = √40000 = 200 feet
Since diagonal of a square is = √2(side)² = side√2 = 200√2 = 200×1.41 = 282.84 feet.
Therefore length of the fence will be = 282.84 ft.
By finding the diagonal of the square, we conclude that the length of the fence must be 282.84 ft.
The length of the fence will be equal to the diagonal of the square.
We know that for a square of side length S, the area is:
A = S^2
In this case, we know that the area is 40,000 ft^2, replacing that in the above equation we get:
40,000 ft^2 = S^2
If we apply the square root on both sides, we get:
S = √(40,000 ft^2)
Now, the diagonal of a square of side length S is:
D = S*√2,
Then we have:
D = √(40,000 ft^2)*√2 = √(80,000 ft^2) = 282.84 ft
The length of the fence must be 282.84 ft.
If you want to learn more about squares, you can read:
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