giselle1398 giselle1398

08-02-2017
Mathematics

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numerical value of cosh(ln5)

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LammettHash LammettHash

08-02-2017

[tex]\cosh x=\dfrac{e^x+e^{-x}}2[/tex]

So

[tex]\cosh(\ln 5)=\dfrac{e^{\ln5}+e^{-\ln5}}2=\dfrac{5+\frac15}2=\dfrac{13}5[/tex]

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