Answer: The area of the poster is 10.53 sq. ft.
Step-by-step explanation: Given that the poster that David bought for an art project is 2.7 ft wide and 3.9 ft tall.
We are to find the area of the poster.
A picture of the poster ABCD is shown in the attached figure. The poster is always in the form of a rectangle with length as its height.
Given,
length of the poster, l = BC = 3.9 ft,
and
width of the poster, w, CD = 2.7 ft.
Therefore, the area of the poster will be
[tex]A=BC \times CD=l\times w=3.9\times 2.7=10.53~\textup{sq. ft.}[/tex]
Thus, the area of the poster is 10.53 sq. ft.
