Respuesta :

mrinconj
This angle t= -76º lies on the IV quadrant, so the reference angle is the acute positive angle fron this angle to x-axis, so in this case the reference angle is 76º. (if better if you can draw it).
Because, the formula for this quadrant is: Ref angle= 360º - given angle (but given angle has to be positive so for -76º turned positive is 284º) now you can apply the formula Ref angle= 360º - 284º= 76º

Answer:  The required reference angle for the angle t is 284°.

Step-by-step explanation:  We are given to find the reference angle for the following angle t :

t = -76°.

We know that

any two reference angles differ by a measurement of 360°.

So, if s represents one of the reference angles for t, then we get

    s = t + 360°

⇒  s = -76° + 360°

⇒  s = 284°.

Thus, the required reference angle for the angle t is 284°.

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