The approximate sum of the lengths of the two sidewalks, shown as dotted lines is 38.21m.
Given that,
Total Length of the garden = 23m
The side length of the square section = 15m
The side length small rectangle section = 23m - 15m = 8 m
We have to find,
The approximate sum of the lengths of the two sidewalks, shown as dotted lines.
According to the question,
The square section,
The side length of the square is 15m.
By using Pythagoras theorem the length of the diagonal:
[tex]( Diagonal )^{2}[/tex] [tex]= (15m)^{2} + (15m)^{2}[/tex] [tex]= 450m^{2}[/tex]
Diagonal = [tex]\sqrt{450m^{2} }[/tex] = 21.21m
The small rectangle section,
The sides of small rectangle are = 23m - 15m = 8 m
Now, By using the Pythagoras theorem:
[tex](Diagonal)^{2} = (8m^{2} ) + (15^{2}m) = 289m^{2}[/tex]
Diagonal = [tex]\sqrt{289m^{2} }[/tex] = 17 m
The sum of the lengths of the diagonals of the two sections is,
= 17m + 21.21 m = 38.21m
Hence, The approximate sum of the lengths of the two sidewalks, shown as dotted lines is 38.21m.
For the more information about Pythagoras Theorem click the link given below.
https://brainly.com/question/20213211