Answer : The number of ions present in 0.187 mole of sodium ions are, [tex]1.163\times 10^{23}[/tex]
Solution : Given,
Moles of sodium ions = 0.187 moles
As we know that
1 mole of substance contains [tex]6.22\times 10^{23}[/tex] number of ions
So, 0.187 moles of substance contains [tex]0.187\times (6.22\times 10^{23})=1.163\times 10^{23}[/tex] number of ions
Therefore, the number of ions present in 0.187 mole of sodium ions are, [tex]1.163\times 10^{23}[/tex]