Answer:
C) 3 x 10^4 meters per second.
Step-by-step explanation:
The earth's orbital speed around the sun is 30 kilometers per second. Since, the given options list the speed in meters per day or meters per second we have to convert speed into these units.
Since,
1 kilometer = 1000 meters, we can write:
[tex]30 \text{ km/sec}=\frac{ 30 km}{sec} \\\\= \frac{30 \times 1000 \text{ meters} }{sec}\\\\= \frac{30000\text{ meters} }{sec}\\\\=\frac{3 \times 10^{4} \text{ meters} }{sec}[/tex]
= 3 x 10^4 meters per second
which matches with the answer in option C.
We obtained the result 30000 m/s. We expressed it using the power of 10 i.e scientific notation using the following steps:
30000 = 3 x 10000 = 3 x 10 x 10 x 10 x 10 = 3 x 10^{4} m/s
Therefore, the earth's orbital speed around the sun is 3 x 10^4 meters per second.
