The perimeter of a rectangle is 68 ft. Find the dimensions of the rectangle if the ratio of the length to the width is 9 : 8. Which of the following would be the best equation to use to solve this problem?
Answers :
Question options:

A 2x + 2x = 68

B (9 + 8) = 68x

C 9x + 8x = 68

D 2(9x) + 2(8x) = 68

Respuesta :

i think the best answer is d since 18x + 16x

The equation will be 2(9k) + 2(8k) = 68.

Mensuration

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

Rectangle

It is a polygon that has four sides and four corners. The sum of the internal angle is 360 degrees. In rectangle opposite sides are parallel and equal and each angle is 90 degrees. And its diagonals are also equal and intersect at mid-point.

Given

The perimeter of a rectangle is 68 ft.

The ratio of the length to the width is 9:8.

To find

The best equation to use to solve this problem.

How do find the best equation to use to solve this problem?

The perimeter of a rectangle is 68 ft.

The ratio of the length (L) to the width (W) is 9:8.

[tex]\rm \dfrac{L}{W} = \dfrac{9}{8} = k\\\\L = 9k \ \ \ \ \ \ W = 8k[/tex]

Then according to the perimeter.

[tex]\begin{aligned} \rm Perimeter &= 2 * (L + W)\\68 &= 2 (8k+9k)\\68 &= 34k\\k &= 2\end{aligned}[/tex]

Then

L = 9k = 9x2 = 18

W = 8k = 8x2 = 16

And equation will be 2(9k) + 2(8k) = 68.

More about the mensuration link is given below.

https://brainly.com/question/10046743